Let, angle ∠AEB=α and ∠...
Let, angle ∠CEB=α, ∠BED=β, ∠ABC=Θ
In the triangle, ABC, Exterior ∠ECD=interior ∠ACB + ∠ABC=900-α+Θ=900-(α-Θ)
In the triangle AEB,AB/Sin ∠AEB=EB/Sin ∠EAB
AB= EB. Sin ∠AEB/Sin ∠EAB
AB=EB. Sin (α-β)/ Sin 900-(α-Θ)
AB=EB. Sin (α-β)/ Cos(α-Θ)
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